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Duckduckgosearch (#1388)
### What problem does this PR solve? #918 Add components: Baidu, Duckduckgo ### Type of change - [x] New Feature (non-breaking change which adds functionality)
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@ -10,6 +10,7 @@ from .message import Message, MessageParam
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from .rewrite import RewriteQuestion, RewriteQuestionParam
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from .rewrite import RewriteQuestion, RewriteQuestionParam
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from .keyword import KeywordExtract, KeywordExtractParam
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from .keyword import KeywordExtract, KeywordExtractParam
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from .baidu import Baidu, BaiduParam
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from .baidu import Baidu, BaiduParam
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from .duckduckgosearch import DuckDuckGoSearch, DuckDuckGoSearchParam
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def component_class(class_name):
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def component_class(class_name):
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@ -50,12 +50,12 @@ class Baidu(ComponentBase, ABC):
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'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/88.0.4324.104 Safari/537.36'}
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'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/88.0.4324.104 Safari/537.36'}
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response = requests.get(url=url, headers=headers)
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response = requests.get(url=url, headers=headers)
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baidu_res = re.findall(r'"contentText":"(.*?)"', response.text)
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url_res = re.findall(r"'url': \\\"(.*?)\\\"}", response.text)
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url_res = re.findall(r"'url': \\\"(.*?)\\\"}", response.text)
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for i in range(min(len(baidu_res), len(url_res))):
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title_res = re.findall(r"'title': \\\"(.*?)\\\",\\n", response.text)
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baidu_res[i] += '<a>' + url_res[i] + '</a>'
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body_res = re.findall(r"\"contentText\":\"(.*?)\"", response.text)
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baidu_res = [re.sub('<em>|</em>', '', '<a href="' + url + '">' + title + '</a> ' + body) for url, title, body
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del url_res
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in zip(url_res, title_res, body_res)]
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del body_res, url_res, title_res
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br = pd.DataFrame(baidu_res, columns=['content'])
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br = pd.DataFrame(baidu_res, columns=['content'])
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print(">>>>>>>>>>>>>>>>>>>>>>>>>>\n", br)
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print(">>>>>>>>>>>>>>>>>>>>>>>>>>\n", br)
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62
graph/component/duckduckgosearch.py
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62
graph/component/duckduckgosearch.py
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@ -0,0 +1,62 @@
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#
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# Copyright 2024 The InfiniFlow Authors. All Rights Reserved.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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#
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import random
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from abc import ABC
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from functools import partial
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from duckduckgosearch import DDGS
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import pandas as pd
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from graph.component.base import ComponentBase, ComponentParamBase
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class DuckDuckGoSearchParam(ComponentParamBase):
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"""
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Define the DuckDuckGoSearch component parameters.
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"""
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def __init__(self):
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super().__init__()
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self.top_n = 10
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self.channel = "text"
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def check(self):
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self.check_positive_integer(self.top_n, "Top N")
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self.check_valid_value(self.channel, "Web Search or News", ["text", "news"])
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class DuckDuckGoSearch(ComponentBase, ABC):
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component_name = "DuckDuckGoSearch"
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def _run(self, history, **kwargs):
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ans = self.get_input()
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ans = " - ".join(ans["content"]) if "content" in ans else ""
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if not ans:
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return Baidu.be_output(self._param.no)
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if self.channel == "text":
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with DDGS() as ddgs:
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# {'title': '', 'href': '', 'body': ''}
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duck_res = ['<a href="' + i["href"] + '">' + i["title"] + '</a> ' + i["body"] for i in
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ddgs.text(ans, max_results=self._param.top_n)]
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elif self.channel == "news":
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with DDGS() as ddgs:
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# {'date': '', 'title': '', 'body': '', 'url': '', 'image': '', 'source': ''}
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duck_res = ['<a href="' + i["url"] + '">' + i["title"] + '</a> ' + i["body"] for i in
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ddgs.news(ans, max_results=self._param.top_n)]
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dr = pd.DataFrame(duck_res, columns=['content'])
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print(">>>>>>>>>>>>>>>>>>>>>>>>>>\n", dr)
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return dr
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