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974a467cf6
### What problem does this PR solve? When I use the categorization operator, I find that if the keyword I want to Categorize appears repeatedly in the input, then I cannot judge the word that appears most frequently. Instead, I simply get the word that matches and return all the ones that have made the following changes to the categorize filter. ### Type of change - [x] Bug Fix (non-breaking change which fixes an issue) - [x] New Feature (non-breaking change which adds functionality) - [x] Refactoring - [x] Performance Improvement
109 lines
3.9 KiB
Python
109 lines
3.9 KiB
Python
#
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# Copyright 2024 The InfiniFlow Authors. All Rights Reserved.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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#
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import logging
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from abc import ABC
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from api.db import LLMType
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from api.db.services.llm_service import LLMBundle
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from agent.component import GenerateParam, Generate
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class CategorizeParam(GenerateParam):
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"""
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Define the Categorize component parameters.
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"""
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def __init__(self):
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super().__init__()
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self.category_description = {}
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self.prompt = ""
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def check(self):
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super().check()
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self.check_empty(self.category_description, "[Categorize] Category examples")
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for k, v in self.category_description.items():
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if not k:
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raise ValueError("[Categorize] Category name can not be empty!")
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if not v.get("to"):
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raise ValueError(f"[Categorize] 'To' of category {k} can not be empty!")
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def get_prompt(self, chat_hist):
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cate_lines = []
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for c, desc in self.category_description.items():
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for line in desc.get("examples", "").split("\n"):
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if not line:
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continue
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cate_lines.append("USER: {}\nCategory: {}".format(line, c))
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descriptions = []
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for c, desc in self.category_description.items():
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if desc.get("description"):
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descriptions.append(
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"\nCategory: {}\nDescription: {}".format(c, desc["description"]))
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self.prompt = """
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Role: You're a text classifier.
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Task: You need to categorize the user’s questions into {} categories, namely: {}
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Here's description of each category:
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{}
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You could learn from the following examples:
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{}
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You could learn from the above examples.
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Requirements:
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- Just mention the category names, no need for any additional words.
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---- Real Data ----
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USER: {}\n
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""".format(
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len(self.category_description.keys()),
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"/".join(list(self.category_description.keys())),
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"\n".join(descriptions),
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"\n\n- ".join(cate_lines),
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chat_hist
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)
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return self.prompt
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class Categorize(Generate, ABC):
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component_name = "Categorize"
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def _run(self, history, **kwargs):
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input = self.get_input()
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input = " - ".join(input["content"]) if "content" in input else ""
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chat_mdl = LLMBundle(self._canvas.get_tenant_id(), LLMType.CHAT, self._param.llm_id)
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ans = chat_mdl.chat(self._param.get_prompt(input), [{"role": "user", "content": "\nCategory: "}],
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self._param.gen_conf())
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logging.debug(f"input: {input}, answer: {str(ans)}")
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# Count the number of times each category appears in the answer.
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category_counts = {}
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for c in self._param.category_description.keys():
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count = ans.lower().count(c.lower())
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category_counts[c] = count
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# If a category is found, return the category with the highest count.
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if any(category_counts.values()):
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max_category = max(category_counts.items(), key=lambda x: x[1])
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return Categorize.be_output(self._param.category_description[max_category[0]]["to"])
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return Categorize.be_output(list(self._param.category_description.items())[-1][1]["to"])
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def debug(self, **kwargs):
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df = self._run([], **kwargs)
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cpn_id = df.iloc[0, 0]
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return Categorize.be_output(self._canvas.get_component_name(cpn_id))
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