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7013d7f620
### What problem does this PR solve? #651 ### Type of change - [x] Bug Fix (non-breaking change which fixes an issue)
79 lines
2.4 KiB
Python
79 lines
2.4 KiB
Python
# -*- coding: utf-8 -*-
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from openpyxl import load_workbook
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import sys
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from io import BytesIO
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from rag.nlp import find_codec
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class RAGFlowExcelParser:
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def html(self, fnm):
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if isinstance(fnm, str):
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wb = load_workbook(fnm)
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else:
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wb = load_workbook(BytesIO(fnm))
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tb = ""
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for sheetname in wb.sheetnames:
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ws = wb[sheetname]
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rows = list(ws.rows)
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if not rows:continue
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tb += f"<table><caption>{sheetname}</caption><tr>"
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for t in list(rows[0]):
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tb += f"<th>{t.value}</th>"
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tb += "</tr>"
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for r in list(rows[1:]):
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tb += "<tr>"
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for i, c in enumerate(r):
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if c.value is None:
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tb += "<td></td>"
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else:
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tb += f"<td>{c.value}</td>"
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tb += "</tr>"
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tb += "</table>\n"
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return tb
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def __call__(self, fnm):
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if isinstance(fnm, str):
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wb = load_workbook(fnm)
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else:
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wb = load_workbook(BytesIO(fnm))
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res = []
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for sheetname in wb.sheetnames:
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ws = wb[sheetname]
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rows = list(ws.rows)
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if not rows:continue
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ti = list(rows[0])
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for r in list(rows[1:]):
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l = []
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for i, c in enumerate(r):
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if not c.value:
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continue
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t = str(ti[i].value) if i < len(ti) else ""
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t += ("：" if t else "") + str(c.value)
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l.append(t)
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l = "; ".join(l)
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if sheetname.lower().find("sheet") < 0:
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l += " ——" + sheetname
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res.append(l)
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return res
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@staticmethod
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def row_number(fnm, binary):
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if fnm.split(".")[-1].lower().find("xls") >= 0:
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wb = load_workbook(BytesIO(binary))
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total = 0
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for sheetname in wb.sheetnames:
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ws = wb[sheetname]
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total += len(list(ws.rows))
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return total
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if fnm.split(".")[-1].lower() in ["csv", "txt"]:
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encoding = find_codec(binary)
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txt = binary.decode(encoding, errors="ignore")
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return len(txt.split("\n"))
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if __name__ == "__main__":
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psr = RAGFlowExcelParser()
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psr(sys.argv[1])
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