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ede733e130
### What problem does this PR solve? add support for eml file parser #1363 ### Type of change - [x] New Feature (non-breaking change which adds functionality) --------- Co-authored-by: Zhedong Cen <cenzhedong2@126.com> Co-authored-by: Kevin Hu <kevinhu.sh@gmail.com>
42 lines
1.6 KiB
Python
42 lines
1.6 KiB
Python
# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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#
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from rag.nlp import find_codec,num_tokens_from_string
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class RAGFlowTxtParser:
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def __call__(self, fnm, binary=None, chunk_token_num=128):
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txt = ""
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if binary:
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encoding = find_codec(binary)
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txt = binary.decode(encoding, errors="ignore")
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else:
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with open(fnm, "r") as f:
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while True:
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l = f.readline()
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if not l:
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break
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txt += l
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return self.parser_txt(txt, chunk_token_num)
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@classmethod
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def parser_txt(cls, txt, chunk_token_num=128):
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if type(txt) != str:
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raise TypeError("txt type should be str!")
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sections = []
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for sec in txt.split("\n"):
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if num_tokens_from_string(sec) > 10 * int(chunk_token_num):
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sections.append((sec[: int(len(sec) / 2)], ""))
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sections.append((sec[int(len(sec) / 2) :], ""))
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else:
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sections.append((sec, ""))
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return sections |